Szathmáry László honlapja @ DEIK | DLang / Operation with every element

It's possible to modify every element of a list without a loop.

(1) Modify every element of a list

import std.stdio;

void main()
{
int[] numbers = [1, 2, 3, 4, 5];
writeln(numbers); // [1, 2, 3, 4, 5]

numbers[] *= 2; // multiply every element by 2
writeln(numbers); // [2, 4, 6, 8, 10]

numbers[] = 3; // set every element to 3
writeln(numbers); // [3, 3, 3, 3, 3]

writeln("---");

int[] others = [21, 22, 23, 24, 25];
// numbers[i] <- others[i]
numbers[] = others; // numbers and others must have the same number of elements
others[0] = -1;
writeln(numbers); // [21, 22, 23, 24, 25]
writeln(others); // [-1, 22, 23, 24, 25]
// numbers and others are independent
}

Note:

At the end, if we wrote numbers = others (notice the lack of []) would mean something else! It would mean that numbers (the reference) points on others. Then numbers and others would point on the same list object.