Szathmáry László honlapja @ DEIK | DLang / Append to a list, extend a list

(1) append, extend
def main(): li = [1, 2, 3] numbers = [50, 60] li.append(4) print(li) # [1, 2, 3, 4] nums1 = li.copy() # [1, 2, 3, 4] (copy) nums1.append(numbers) print(nums1) # [1, 2, 3, 4, [50, 60]] nums2 = li.copy() # [1, 2, 3, 4] (copy) nums2.extend(numbers) print(nums2) # [1, 2, 3, 4, 50, 60]	import std.stdio; void main() { int[] li = [1, 2, 3]; int[] numbers = [50, 60]; li ~= 4; writeln(li); // [1, 2, 3, 4] auto nums1 = li.dup; // [1, 2, 3, 4] (copy) nums1 ~= numbers; writeln(nums1); // [1, 2, 3, 4, 50, 60] writeln(li); // [1, 2, 3, 4] }

In D, you can append to a list with the ~= operator. If you append a single element, it'll be added. If you append another list, then each element of it will be appended. That is, it works similarly to Python's list.extend() method.

Create a list of lists

(2) list of lists
def main(): li1 = [1, 2, 3] li2 = [50, 60] result = [] result.append(li1) result.append(li2) print(result) # [[1, 2, 3], [50, 60]]	import std.stdio; void main() { int[] li1 = [1, 2, 3]; int[] li2 = [50, 60]; int[][] result; // list of lists (2D) result ~= li1; result ~= li2; writeln(result); // [[1, 2, 3], [50, 60]] }