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String → list of chars

(1) string → list of chars
def main():
    s = "görög"

    chars = list(s)

    # string -> list of chars
    print(chars)  # ['g', 'ö', 'r', 'ö', 'g']

    # remove duplicated chars from a string
    print(list(set(list(s))))  # ['r', 'ö', 'g']
import std.stdio;
import std.algorithm;
import std.conv;

void main()
{
    string s = "görög";

    auto a = s.dup;
    writeln(a); // görög
    writeln("a length: ", a.length); // 7

    // string -> list of chars
    auto b = s.dup.to!(dchar[]);
    writeln(b); // görög
    writeln("b length: ", b.length); // 5

    // remove duplicated chars from a string
    string result = s.dup
        .to!(dchar[])
        .sort
        .uniq
        .to!string;
    writeln(result); // grö
}

Notes for D:

  • A string is UTF-8 encoded. The function dup() converts an immutable string to a mutable char array (char[]). However, this char array contains UTF-8 bytes, hence the length of a is 7 (7 bytes, since "ö" is represented on 2 bytes).
  • A char array can be converted to a dchar array (dchar[]). Now the length of b is 5. It has 5 elements, but now every element (every dchar) occupies 4 bytes. A dchar can hold any Unicode value.
  • A dchar array can now be sorted.
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Page last modified on 2025 July 09, 21:27