Szathmáry László honlapja @ DEIK | DLang / Reading from stdin

See std.stdio.

(1) `readf()`
#include <stdio.h> int main() { int a, b; printf("N1: "); scanf("%d", &a); printf("N2: "); scanf("%d", &b); printf("Sum: %d\n", a + b); return 0; }	#!/usr/bin/env rdmd import std.stdio; // readf() void main() { int a, b; write("N1: "); readf(" %s", &a); write("N2: "); readf(" %s", b); // the & can be omitted writefln("Sum: %s", a + b); // writefln("Sum: %d", a + b); // also good }

readf(" %s", &a);

Notes:

The space before %s means: skip the whitespaces. It's always a good idea to do this, otherwise a previous newline character can stuck in the stdin and will cause problems when you want to use readf() again.
The %s placeholder is different from C's %s! Here it means: suitable, i.e. convert the value to a suitable type. It's a joker solution. D looks at the type of the variable (here: int), and the value will be converted to this type.
In writefln(), %s means the same as before: suitable type. It'll mean the type of the value that we want to print (here: int). Of course, you can also specify the type manually (like %d for instance).

Example

(1) get_int()

import std.stdio;

int get_int(const string msg)
{
int n;

write(msg);
readf(" %s", n);
return n;
}

void main()
{
int n = get_int("n: ");
writefln("n is %s", n);
}

n: 7
n is 7