fixpont-iteráció¶
y′=f(t,y) y(a)=b
y(t)=b+∫taf(s,y(s))ds
y→T(y), ahol T(y)(t)=b+∫taf(s,y(s))ds
yn→yn+1=T(yn), ahol T(yn)(t)=b+∫taf(s,yn(s))ds
f(t,y)=t−y, y0(t)=1
y1(t)=1+∫t0(s−1)ds=1−t+t22
y2(t)=1+∫t0(s−1−s22+s)ds=1−t+t2−t36
y3(t)=1+∫t0(s−1+s−s2+s36)ds=1−t+t2−t33+t424
y4(t)=1+∫t0(s−1+s−s2+s33−t424)ds=1−t+t2−t33+t412−t5120